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bitwise AND
class MainClass
{
public static void Main()
{
byte byte1 = 0x9a; // binary 10011010, decimal 154
byte byte2 = 0xdb; // binary 11011011, decimal 219
byte result;
System.Console.WriteLine("byte1 = " + byte1);
System.Console.WriteLine("byte2 = " + byte2);
result = (byte) (byte1 & byte2);
System.Console.WriteLine("byte1 & byte2 = " + result);
}
}
byte1 = 154
byte2 = 219
byte1 & byte2 = 154
Use bitwise AND to determine if a number is odd.
using System;
class Example {
public static void Main() {
ushort num;
num = 10;
if((num & 1) == 1)
Console.WriteLine("This won"t display.");
num = 11;
if((num & 1) == 1)
Console.WriteLine(num + " is odd.");
}
}
11 is odd.
Use bitwise AND to make a number even
using System;
class Example {
public static void Main() {
ushort num;
ushort i;
for(i = 1; i <= 10; i++) {
num = i;
Console.WriteLine("num: " + num);
num = (ushort) (num & 0xFFFE); // num & 1111 1110
Console.WriteLine("num after turning off bit zero: "
+ num + "\n");
}
}
}
num: 1
num after turning off bit zero: 0
num: 2
num after turning off bit zero: 2
num: 3
num after turning off bit zero: 2
num: 4
num after turning off bit zero: 4
num: 5
num after turning off bit zero: 4
num: 6
num after turning off bit zero: 6
num: 7
num after turning off bit zero: 6
num: 8
num after turning off bit zero: 8
num: 9
num after turning off bit zero: 8
num: 10
num after turning off bit zero: 10